Thanks,

Gabriel ]]>

Putting any customary introduction aside, I can only assume you are using random number generation in the rolling routine given the multimillion number of rolls. I approached the problem from a more organized approach if I may be so bold. “Base Six Esque” (nested loops 6 deep). Every possible throw of the dice analyzed one at a time, evaluated to achieve the highest scoring configuration and incrementing that configurations variable, then cycling through the nested loop to eval. the next possible roll in the sequence. I.E.

if (111111){ six of a kind++;)//other configs ! incremented

111111

111112

111113

.

.

.

666664

666665

666666

All 46656 one at a time. I then used the same technique for five dice rolls, four dice rolls, three dice rolls etc.

I’ve generated data tables and was wondering if you would take a look at them.

email me at greggroessger@yahoo.com and I’ll reply with a text file attachment. Or a way of your choosing.

]]>Our local tavern has a roll of the day game that I believe the odds of winning anything let alone the pot are astronomical.

Here is the game…

You get 10 die and 2 rolls for $1.00. When you roll the first time you pull out whatever die you have the most of, say 4 two’s. You have 6 remaining for your 2nd roll. Let’s say you get 3 more two’s. Now for an extra $1.00 you can buy a third roll.

I see in one of the charts above that using 6 die that the odds of getting 6 of a kind are 1 in 7776, 5 of a kind are 1 in 259.2 etc.

My question is: Using ten (10) die, in the two initial rolls’ what are the odds of getting 1 of a kind, 2 of a kind etc. up to 10 of a kind?

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